In the reaction CH_3-CH=CH_2 + H_2O + [O] xri | vedclass

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(B) The reaction involves the oxidation of propene to propane-$1,2$-diol,followed by oxidative cleavage.The cleavage of propane-$1,2$-diol $(CH_3-CH(O

Vedclass · Accepted Answer

$CH_3-COOH$

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(B) The reaction involves the oxidation of propene to propane-$1,2$-diol,followed by oxidative cleavage.The cleavage of propane-$1,2$-diol $(CH_3-CH(OH)-CH_2(OH))$ using an oxidizing agent leads to the breaking of the $C-C$ bond between the two hydroxyl-bearing carbons.This process yields ethanoic acid $(CH_3COOH)$ and methanoic acid $(HCOOH)$.Therefore,$X$ is $CH_3COOH$.

In the reaction $CH_3-CH=CH_2 + H_2O + [O]$ $\xrightarrow[Acid]{KMnO_4} CH_3-CH(OH)-CH_2(OH)$ $\xrightarrow{[O]} X + HCOOH$,$X$ is:

Similar Questions

What is the correct order of reactivity of alkenes towards acid-catalyzed hydration to form alcohols?

What is the total number of alkenes obtained in the following reaction?
$CH_3CH_2CH_2CH(OH)CH_3 \xrightarrow{H^+, \Delta} \text{Products}$

Which of the following alkenes yield $3-$bromo$-3-$methylpentane as the major product upon addition of $HBr$?
$(I)$ $3-$methylpent$-2-$ene
$(II)$ $3-$methylpent$-2-$ene (isomer)
$(III)$ $3-$ethylpent$-1-$ene
$(IV)$ $3-$methylpent$-1-$ene

$X$ is

Explain the reaction of propene with $HBr$.

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